$6r+5=11r\ \ \ \ |\text{subtract 6r from both sides}\\\\5=5r\ \ \ \ |\text{divide both sides by 5}\\\\\boxed{r=1}\\-------------------------\\\dfrac{2x-4}{2}=6x+3\\\\\dfrac{2x}{2}-\dfrac{4}{2}=6x+3\\\\x-2=6x+3\ \ \ \ \ |\text{add 2 to both sides}\\\\x=6x+5\ \ \ \ |\text{subtract 6x from both sides}\\\\-5x=5\ \ \ \ \ |\text{divide both sides by -5}\\\\\boxed{x=-1}$

6 0

2 years ago

A bookstore sells textbooks for $80 each and notebooks for $4 dollars each. The bookstore would like to sell $800 in merchandise

mariarad [96]

Answer: 8 textbooks

Step-by-step explanation:

Sold 40 notebooks = 40 x $4 = $160

$800 - $160 = $640 left to sell

$640/$80 (cost of textbook) = 8 textbooks need to be sold

3 0

2 years ago

Jed Sites

g100num [7]

Answer:

Option B: 3x + 3y - 3

Step-by-step explanation:

In an isosceles triangle, the two congruent sides are equal.

We are told the base is; x - y - 2 units

Now let each of the congruent sides be represented as A.

Thus the perimeter equation will be;

P = 2A + x - y - 2

Now, we are told that the perimeter is; 7x + 5y - 8 units

Thus;

7x + 5y - 8 = 2A + x - y - 2

Rearranging gives;

7x - x + 5y + y - 8 + 2 = 2A

2A = 6x + 6y - 6

Divide through by 2 to give;

A = 3x + 3y - 3 units

6 0

2 years ago