All categories

2 years ago

1. Find the domain and range of the relation and determine whether it is a function.

Mathematics

1 answer:

Katyanochek1 [597]2 years ago

8 0

A. the relation is a function

You might be interested in

Please help..Thanks:)

finlep [7]

From top to bottom: 16, 5, 28. Please give me 'brainliest answer?

8 0

2 years ago

Read 2 more answers

The muzzle velocity of an ancient cannon was about 420ft/s. What is the cannonball's speed in miles per hour?

Sholpan [36]

286.36mph. ( .36 is a repeating decimal )

4 0

2 years ago

Completely factored form of xy^3 – x^3y?

Zolol [24]

Answer:

xy(y - x)(y + x)

Step-by-step explanation:

take out a common factor xy from both terms

= xy(y² - x²)

y² - x² is a difference of squares and factors in general as (y - x)(y + x)

Hence

xy³ - x³y = xy(x - y)(x + y)

8 0

2 years ago

What is the height of this triangle?

nikklg [1K]

A = 1/2 b h
5 = 1/2 (5) h
10 = 5h
h = 10/5
h = 2

answer
2

7 0

2 years ago

Read 2 more answers

Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea

lord [1]

Answer:

a) 17.5

b) 15.6

c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

$\int\limits^y_0 {kx^{2} } \, =1$

where y=23

Clearing k=0.00025

a) $Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5$

b) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2} =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6$

c) The function is equal to:

f(x)=k(1+2x)

$\int\limits^y_0 {k(1+2x)} \, =1$

where y=20

k=0.0024

$Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3$

d) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2} =198.4-176.89=21.51$

8 0

2 years ago