The mass of a NaCl solution that is required to prepare 0.40 L of a 0.75 M solution is 17.55g. Details about mass can be found below.
<h3>How to calculate mass?</h3>
The mass of a substance can be calculated by multiplying the number of moles by its molar mass.
However, the number of moles of a solution must be initially calculated by using the following formula:
molarity = no of moles ÷ volume
no of moles = 0.75 × 0.40
no of moles = 0.3 moles
mass of NaCl = 0.3 × 58.5 = 17.55g
Therefore, the mass of a NaCl solution that is required to prepare 0.40 L of a 0.75 M solution is 17.55g.
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Answer:
Molarity = 0.24 M
Explanation:
Given data:
Number of moles of Mg(NO₃)₂ = 0.181 mol
Volume of solution = 0.750 L
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
by putting values,
Molarity = 0.181 mol / 0.750 L
Molarity = 0.24 M
Answer:
The grams of sodium chloride that will be made is 292.5 g. calculation. 2Na + Cl₂ → 2NaCl. step 1: calculate the moles of Na. moles = mass/molar mass. From periodic table the molar mass of Na = 23 g/mol. moles = 115 g/23 g / mol = 5 moles. Step 2 : use the mole ratio to determine the moles of NaCl. Na:NaCl is 2:2 = 1:1 therefore the moles of NaCl is also = 5 moles.
Explanation:
We know sodium is a very active metal and chlorine is also a very reactive non-metal. Usually, metals like to eliminate electrons and non-metals such as halogens like to accept electrons. Sodium readily eliminate its last shell electrons become Na+ cation and chlorine accepts that electron to form Cl-anion.
