98.857g Na
To find this, set up an equation as so:
4.3 mol Na =
Multiply everything on the top and divide that by everything on the bottom to get the final answer of 98.857g Na.
Hope this helps!
Answer:
M₂ = 0.0745 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = 0.0952 M
V₁ = 38.73 mL
M₂ = ?
V₂ = 49.48 mL
Using the above formula , the molarity of ammonia , can be calculated as ,
0.0952 M * 38.73 mL = M₂* 49.48 mL
the correct answer is B
hope it helps !!!
The bonds in no2− relative to n−o
Taking into account the definition of calorimetry, sensible heat and latent heat, the specific heat capacity of the material is 0.203 .
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
The amount of heat a body receives or transmits is determined by:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
Replacing in the definition of amount of heat:
1220 calories= c× 100 g× 60 C
Solving:
c= 1220 calories÷ (100 g× 60 C)
<u><em>c= 0.203 </em></u>
Finally, the specific heat capacity of the material is 0.203 .
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