Answer:
x = 1/3 + sqrt(5/2)/3 or x = 1/3 - sqrt(5/2)/3
Step-by-step explanation:
Solve for x:
6 x^2 - 4 x = 1
Divide both sides by 6:
x^2 - (2 x)/3 = 1/6
Add 1/9 to both sides:
x^2 - (2 x)/3 + 1/9 = 5/18
Write the left hand side as a square:
(x - 1/3)^2 = 5/18
Take the square root of both sides:
x - 1/3 = sqrt(5/2)/3 or x - 1/3 = -sqrt(5/2)/3
Add 1/3 to both sides:
x = 1/3 + sqrt(5/2)/3 or x - 1/3 = -sqrt(5/2)/3
Add 1/3 to both sides:
Answer: x = 1/3 + sqrt(5/2)/3 or x = 1/3 - sqrt(5/2)/3
Answer:
4-4
Step-by-step explanation:
Substitute the actual values of the points into the distance formula.
Answer:
The value of 
is 10.
Step-by-step explanation:
If APR and SPL are vertical angles, then we get that 
. Given that 
and 
, we find that the value of is:
The value of is 10.
Set up a proportion.
The total side of the “top” line is 8 + 10 = 18. The total side of the “bottom” line is 45. This makes the ratio 18/45.
Now we are trying to find the “larger” bottom segment, let it be x. Because the lines are parallel, the ratio of the “larger” top and bottom segments is equal to the ratio of the whole top and bottom lines.
So 18/45 = 10/x
Reduce 2/5 = 10/x
Cross multiply 2x = 50
Solve x = 25
Answer:
The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:
And the 90% confidence interval would be given (0.131;0.169).
Step-by-step explanation:
We have the following info given:
represent the sampel size slected
number of students who read above the eighth grade level
The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:
The confidence interval for the proportion would be given by this formula
For the 90% confidence interval the significance is 
and 
, with that value we can find the quantile required for the interval in the normal standard distribution and we got.
And replacing into the confidence interval formula we got:
And the 90% confidence interval would be given (0.131;0.169).
