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2 years ago

6

Isaac buys water to make tea for all his friends. He buys 1 quart of water and 1/8 gallon of water . How many cups of water does

he buy?

1 answer:

Aliun [14]2 years ago

7 0

Answer:

6 cups.

Step-by-step explanation:

1 quart of water = 4 cups.

1/8 gallon of water = 2 cups.

4 + 2 = 6 cups

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Question 9 (5 points)

DochEvi [55]

Answer:

D

Step-by-step explanation:

8 0

2 years ago

Tobias sent a chain letter to his friends, asking them to forward the letter to more friends. The number of people who receive t

malfutka [58]

Answer:

$P(t)=37\times (4)^{(t/9.1)}$

Explanation:

The number of emails is multiplied by <em>4</em> every <em>9.1 weeks.</em>

Thus, since <em>Tobias initially sent the chain letter to 37 friends</em>, the number of letters will grow as per this geometric series:

Start: 37 letters

In 9.1 weeks: 37 × 4

In 2 × 9.1 weeks: 37 × (4)²

In 3 × 9.1 weeks: 37 × (4)³

As you see, the exponent is the number of weeks divided by 9.1

Thus, if your variable is the number of weeks, t, then the exponent is t/9.1

And the exponential function, P(t) will be:

$P(t)=37\times (4)^{(t/9.1)}$

3 0

2 years ago

a cargo plane flew to the maintenance facility and back. it took one hour less time to get there than it did to get back. The av

polet [3.4K]

The trip took 57 hour

7 0

2 years ago

When the effective interest rate is 9% per annum, what is the present value of a series of 50 annual payments that start at $100

ser-zykov [4K]

Answer:

$1,109.62

Step-by-step explanation:

Let's first compute the <em>future value FV.</em>

In order to see the rule of formation, let's see the value (in $) for the first few years

<u>End of year 0</u>

1,000

<u>End of year 1(capital + interest + new deposit)</u>

1,000*(1.09)+10

<u>End of year 2 (capital + interest + new deposit)</u>

(1,000*(1.09)+10)*1.09 +10 =

$\bf 1,000*(1.09)^2+10(1+1.09)$

<u>End of year 3 (capital + interest + new deposit)</u>

$\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)$

and we can see that at the end of year 50, the future value is

$\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}$

The sum

$\bf 1+1.09+(1.09)^2+...+(1.09)^{49}$

is the <em>sum of a geometric sequence </em>with common ratio 1.09 and is equal to

$\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356$

and the future value is then

$\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564$

The <em>present value PV</em> is

$\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62$

rounded to the nearest hundredth.

5 0

2 years ago

Suppose a varies directly as b, and a=7 when b=2 find b when a =21

kozerog [31]

Because α varies directley to β
$\alpha = k \beta$
(k = constant)

α=7 when β=2
7= 2k
k= $\frac{7}{2}$

so when α=21
21= $\frac{7}{2}$ b
b= 6

6 0

2 years ago