Answer:
Find a polynomial function whose graph passes through (6,13), (9,-11), (0,5)
1 Answers
Assuming a quadratic, we have that
y = ax^2 + bx + c
Since (0,5) is on the graph, c =5
And we have the remaining system
a(9)^2 + b(9) + 5 = -11
a(6)^2 + b(6) + 5 = 13 simplify
81a + 9b = -16 multiply through by 6 ⇒ 486a + 54b = - 96 (1)
36a + 6b = 8 multiply through by -9 ⇒ -324a -54b = -72 (2)
Add (1) and (2)
162a = -168
a = -28/27
To find b we have
36 (-28/27) + 6b = 8
-112/3 + 6b = 8
⇒ b = 68/9
The function is
y = - (28/27)x^2 + (68/9)x + 5
an example would be: 9x+5m/2=24
because the variables are x and m
the numbers are 9, 5, 2, and 24
and the operation symbols are +, /, and =
Answer:
(-10, 2)
Step-by-step explanation:
Compare:
g(x) = (x+10)^2+2
f(x) = (x - h)^2 + k
Matching these up, term by term, we see that h = -10 and k = 2. (h, k) represents the vertex of the parabola f(x) = (x - h)^2 + k.
We conclude that the vertex of this parabola is (-10, 2).
Divide 50 by 22: 2.27272727...
Round up to hundredth and your final answer is 2.27
hope that helps :)
Answer:
any value of y >= 8
Step-by-step explanation:
