Answer:
A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola
y=5−x^2. What are the dimensions of such a rectangle with the greatest possible area?
Width =
Height =
Width =√10 and Height
Step-by-step explanation:
Let the coordinates of the vertices of the rectangle which lie on the given parabola y = 5 - x² ........ (1)
are (h,k) and (-h,k).
Hence, the area of the rectangle will be (h + h) × k
Therefore, A = h²k ..... (2).
Now, from equation (1) we can write k = 5 - h² ....... (3)
So, from equation (2), we can write
For, A to be greatest ,
⇒
⇒
⇒
Therefore, from equation (3), k = 5 - h²
⇒
Hence,
Width = 2h =√10 and
Height =
Answer:
False solution; [1⅐, -3 3⁄7]
Step-by-step explanation:
{x - 2y = 8
{4x - y = 8
-¼[4x - y = 8]
{x - 2y = 8
{-x + ¼y = -2 >> New Equation
____________
-1¾y = 6
y = -3 3⁄7 [Plug this back into both equations to get the x-coordinate of 1⅐]; 1⅐ = x
I am joyous to assist you anytime.
30 tens=ones is not right so it should be 30 tens=hundreds
Answer:
domain- -2,2,3,5,5 range- -3,1,7,12,12
Step-by-step explanation:
depending on teacher, you may only put the two 5 and the two 12 once, but some teachers require both.