2 years ago

How do I solve this ?

Mathematics

1 answer:

noname [10]2 years ago

8 0

The answer is around 29

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docker41 [41]

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2 years ago

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is picking out some movies to rent, primarily interested in horror films and comedies. He has narrowed down his selections to 15

tigry1 [53]

Answer: 31,365

Step-by-step explanation:

Given : The number of horror films = 15

The number of comedies = 18

Then , the number of different combinations of 4 movies can he rent if he wants at least two comedies is given by :-

$^{18}C_2\times ^{15}C_2+^{18}C_3\times ^{15}C_1+^{18}C_4\times ^{15}C_0\\\\=\dfrac{18!}{2!(18-2)!}\times\dfrac{15!}{2!(15-2)!}+\dfrac{18!}{3!(18-3)!}\times\dfrac{15!}{1!(15-1)!}+\dfrac{18!}{4!(18-4)!}\times\dfrac{15!}{0!(15-0)!}\\\\=16065+12240+3060=31365$