Answer:
Explanation:
mass of object, m = 3 kg
spring constant, K = 750 n/m
compression, x = 8 cm = 0.08 m
angle of gun, θ = 30°
(a) As the ball is launched, it has some velocity due to the compression in the spring, so it has some kinetic energy.
(b) Let v be th evelocity of ball at the tim eof launch.
by using the conservation of energy
1/2 Kx² = 1/2 mv²
750 x 0.08 x 0.08 = 3 x v²
v = 1.265 m/s
By use of the formula of maximum height
h = 0.02 m
h = 2 cm
Answer: 5.96m/s
Explanation:
Given the following :
Mass of car (m) = 1500kg
Velocity (V) = 5.25m/s
Forward force of engine = 1250N
Diatance moved = 4.8m
Final Velocity =?
Final kinetic energy = Initial kinetic energy + work done by engine
Initial kinetic energy = 0.5 × mass × velocity^2
Initial kinetic energy = 0.5 × 1500 × 5.25^2
Initial kinetic energy = 20671.875 J
Work done by engine = Force × distance
Work done by engine = 1250 × 4.8 = 6000J
Final kinetic energy = (20671.875 + 6000) J
= 26671.875 J
From kinetic energy = 0.5mv^2
26671.875 = 1/2 × 1500 × v^2
53343.75 = 1500v^2
v^2 = 35.5625
v = sqrt(35.5625)
v = 5.96m/s
Answer:
Because of the frictional force, the net force will oppose direction of the block and be directed towards the left even tho the spring exerts no force at this point
Answer:
if you look it up i think u can find it it could be a mealltiod Co 27
Explanation: