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2 years ago

Solve the equation 2x-1=13.

Mathematics

2 answers:

netineya [11]2 years ago

8 0

Answer:

Step-by-step explanation:

2 time 7 = 14-1 = 13

tiny-mole [99]2 years ago

5 0

Answer:

x=7

Step-by-step explanation:

Collect like terms

2x=13+1.

2x=14

Divide both side by 2

$\frac{2x}{2} = \frac{14}{2}$

x=7

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Answer:

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Step-by-step explanation:

Add the 2 numbers

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2 years ago

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Parker reviews his homework before he turns it in. When he sees the equation 1.02 divided by 0.6= 0.17, he knows it is wrong. He

HACTEHA [7]

Answer:

The result of the division of a number by a fraction is larger than the fraction.

Step-by-step explanation:

Here,we note that value Parker divided by 0.6. =1.02

Written down result of the division = 1.02/0.6 = 0.17

However, since the numerator is 1.02, then the result of dividing it by a fraction should yield a higher number instead of 0.17

Therefore we check as follows

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The error is apparently due to dividing 1.02 by 6 rather than 0.6

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2 years ago

Use the "mixed partials" check to see if the following differential equation is exact.

Nadya [2.5K]

Answer:

The equation is exact

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Step-by-step explanation:

The step by step explanation and to ascertain the exactness of the differential equation is as shown in the attached file.

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2 years ago

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Travka [436]

Answer:

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Step-by-step explanation:

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1 year ago

The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen

e-lub [12.9K]

Answer with Step-by-step explanation:

Since the given event is binary we can use Bernoulli's probability to sove the problem

Thus for an event 'E' with probability of success 'p' the probability that the event occurs 'r' times in 'n' trails is given by

$P(E)=\frac{n!}{(n-r)!\cdot r!}\cdot p^{r}\cdot (1-p)^{n-r}$

Part a)

For part a n = 11 , r =9, p = 0.75

Applying values we get

$P(E)=\frac{11!}{(11-9)!\cdot 9!}\cdot (0.75)^{9}\cdot (1-0.75)^{11-9}\\\\\therefore P(E)=0.2581$

Part b)

For part b n = 20 , r = 16 , p=0.75

Applying values we get

$P(E)=\frac{20!}{(20-16)!\cdot 16!}\cdot (0.75)^{16}\cdot (1-0.75)^{20-16}\\\\\therefore P(E)=0.1896$

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2 years ago