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2 years ago

How to do it not sure I tried but not sure

Chemistry

1 answer:

never [62]2 years ago

6 0

Answer:

Mass = 17.28 g

Explanation:

Given data:

Mass of propane = 35 g

Volume of oxygen = 27 L

Mass of water produced = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

First of all we will calculate the number of moles of oxygen at STP.

PV = nRT

n = PV/RT

n = 1 atm×27 L / 0.0821 atm. L/ mol.K × 273 K

n = 27 atm . L / 22.413 atm. L/mol

n = 1.2 mol

Moles of propane:

Number of moles = mass/ molar mass

Number of moles = 35 g/ 44.1 g/mol

Number of moles = 0.8 mol

Now we will compare the moles of water with propane and oxygen.

C₃H₈ : H₂O

1 : 4

0.8 : 4×0.8 = 3.2 mol

O₂ : H₂O

5 : 4

1.2 : 4/5×1.2 = 0.96 mol

Number of moles of water produced by oxygen are less so it will limiting reactant.

Mass of water:

Mass = number of moles × molar mass

Mass = 0.96 mol × 18 g/mol

Mass = 17.28 g

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Leya [2.2K]

Hi. 2fouls! :)

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3 0

2 years ago

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The equilibrium 2NO(g)+Cl2(g)⇌2NOCl(g) is established at 500 K. An equilibrium mixture of the three gases has partial pressures

QveST [7]

Answer:

For A: The $K_p$ for the given reaction is $4.0\times 10^1$

For B: The $K_c$ for the given reaction is 1642.

Explanation:

The given chemical reaction follows:

$2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)$

For A:

The expression of $K_p$ for the above reaction follows:

$K_p=\frac{(p_{NOCl})^2}{(p_{NO})^2\times p_{Cl_2}}$

We are given:

$p_{NOCl}=0.24 atm\\p_{NO}=9.10\times 10^{-2}atm=0.0910atm\\p_{Cl_2}=0.174atm$

Putting values in above equation, we get:

$K_p=\frac{(0.24)^2}{(0.0910)^2\times 0.174}\\\\K_p=4.0\times 10^1$

Hence, the $K_p$ for the given reaction is $4.0\times 10^1$

For B:

Relation of $K_p$ with $K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$

where,

$K_p$ = equilibrium constant in terms of partial pressure = $4.0\times 10^1$

$K_c$ = equilibrium constant in terms of concentration = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = 500 K

$\Delta ng$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-3=-1$

Putting values in above equation, we get:

$4.0\times 10^1=K_c\times (0.0821\times 500)^{-1}\\\\K_c=\frac{4.0\times 10^1}{(0.0821\times 500)^{-1})}=1642$

Hence, the $K_c$ for the given reaction is 1642.

7 0

2 years ago

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Genrish500 [490]

Answer:

Liquid

Explanation:

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2 years ago

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You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute b

alexdok [17]

Answer:

0.045 L or 45 mL

Explanation:

Moles = Mass/M.Mass

Moles = 10 g / 109.94 g/mol

Moles = 0.09 moles

Also,

Molarity = Moles / Vol in L

Or,

Vol in L = Moles / Molarity

Vol in L = 0.09 mol / 2 mol/L

Vol in L = 0.045 L

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1 year ago

Nuclei may be unstable if they have

weqwewe [10]

Nuclei may be unstable if they have
a too much energy.
b too many protons.
C an unstable ratio of protons to neutrons.
d any of the above.

The answer would be, D any of the above.
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2 years ago