Answer: its x = 3
Step-by-step explanation:
The maximum or minimum of a quadratic function occurs at
x
=
−
b
2
a
. If
a
is negative, the maximum value of the function is
f
(
−
b
2
a
)
. If
a
is positive, the minimum value of the function is
f
(
−
b
2
a
)
.
f
min
x
=
a
x
2
+
b
x
+
c
occurs at
x
=
−
b
2
a
Find the value of
x
equal to
−
b
2
a
.
x
=
−
b
2
a
Substitute in the values of
a
and
b
.
x
=
−
−
12
2
(
2
)
Remove parentheses.
x
=
−
−
12
2
(
2
)
Simplify
−
−
12
2
(
2
)
.
Tap for more steps...
x
=
3
The maximum or minimum of a quadratic function occurs at
x
=
−
b
2
a
. If
a
is negative, the maximum value of the function is
f
(
−
b
2
a
)
. If
a
is positive, the minimum value of the function is
f
(
−
b
2
a
)
.
f
min
x
=
a
x
2
+
b
x
+
c
occurs at
x
=
−
b
2
a
Find the value of
x
equal to
−
b
2
a
.
x
=
−
b
2
a
Substitute in the values of
a
and
b
.
x
=
−
−
12
2
(
2
)
Remove parentheses.
x
=
−
−
12
2
(
2
)
Simplify
−
−
12
2
(
2
)
.
Tap for more steps...
x
=
3
Answer:
The factors for 5 are going to be 1 and 5 or their negative counterparts, since no other whole number within the range of 5 can be multiplied to get 5.
Make sense?
Answer:
measure of supplementary angle 180-69.3=110.7
<span>Let time taken by Luke to cover the distance = x hours
Speed of Luke = 6 miles per hour
Therefore, Distance covered by Luke = 6x ------(1)
Speed of Micah = 4 miles per hour
Since Micah walked 2 miles before Luke started running, Luke started 1/2 an hour after Micah started.
Therefore time taken by Micah to cover the distance = x+1/2
Distance covered by Micah = 4(x + 1/2) -------(2)
Equating (1) and (2)
6x = 4(x+1/2)
6x = 4x +2
2x = 2
x= 1
Therefore Luke would take 1 hour to cover the distance covered by Micah.</span>
four since it has four edges/sides