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2 years ago

To be able to compete in a particular class, a bodybuilder can weigh in at no more than

Mathematics

1 answer:

adell [148]2 years ago

4 0

Answer:

Range of weight = 176 - 146 pound

Step-by-step explanation:

Given:

Maximum weight = 175 pound

Minimum weight = 145 pound

Clothes weight = 1 pound

Find:

Range of weight

Computation:

Range = maximum weight - 1 pound

Range = minimum weight + 1 pound

Range = 175 - 1 pound

Range = 145 + 1 pound

Range = 174

Range = 146

Range of weight = 176 - 146 pound

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The volume of the cylinder above is 2,314.25, and the radius of the base is 8.9 Find the volume of the cone.

olga55 [171]

Answer: $771.41\ units^3$

Step-by-step explanation:

The missing figure is attached.

The volume of an oblique cylinders and the volume of a right cylinder can be found with this formula:

$V_{cy}=\pi r^2h$

Where "r" is the radius and "h" is the height.

The volume of an oblique cone and the volume of a right cone can be found with this formula:

$V_{co}=\frac{1}{3}\pi r^2h$

Where "r" is the radius and "h" is the height.

According to the information given in the exercise, you know that the volume of the cylinder and also the radius of the cylinder and the cone ,are the following:

$V_{cy}=2,314.25\ units^3\\\\r=8.9\ units$

Therefore, in order to find the volume of the cone, you only need to multiply the volume of the cylinder by $\frac{1}{3}$ .

Then, you get:

$V_{co}=\frac{1}{3}(2,314.25\ units^3)\\\\V_{co}=771.41\ units^3$

8 0

2 years ago

Read 2 more answers

Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur

Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

$\sigma$ is parameterized by

$\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle$

for $0\le u\le7$ and $0\le v\le\frac{2\pi}3$ , and a normal vector to this surface is

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle$

with norm

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}$

So the integral of $f(x,y,z)=x^2+y^2+z^2$ is

$\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}$

6 0

2 years ago

Help me please ASAP!

Bumek [7]

$216 = 6^{4x+ 11}$

$6^3 = 6^{4x+ 11}$

$3 = 4x + 11$

$4x = 3 - 11$

$4x = -8$

$x = -2$

Answer: (c) x = -2

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2 years ago

Please help find the Measure of 1 step by step

maks197457 [2]

Answer: 112°

Step-by-step explanation:

a straight line only has 180° at all times so it is a matter of subtraction. 180-68 is 112° so from there you can find #2 as 68°, #3 as 90° and #4 as 90°, and so on.

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2 years ago

How do I solve this math problem?

nikitadnepr [17]

1,088 if you set it up as a proportion. It would be 17/20 compared to x/1280 multiply 17 by 1280 and then divide by 20.

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2 years ago