Algebra write a mixed number 64 piece so that 314 times P is more than three one fourth

Mathematics

1 answer:

Novay_Z [31]2 years ago

6 0

314P > 3 1/4 I think is what you're looking for.

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What's the area of this rectangle?

Bess [88]

well, the assumption is that is a rectangle, namely it has two equal pairs, so we can just find the length of one of the pairs to get the dimensions.

hmmmm let's say let's get the length of the segment at (-1,-3), (1,3) for its length

and

the length of the segment at (-1, -3), (-4, -2) for its width

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{length}{L}=\sqrt{[1-(-1)]^2+[3-(-3)]^2}\implies L=\sqrt{(1+1)^2+(3+3)^2} \\\\\\ L=\sqrt{4+36}\implies L=\sqrt{40} \\\\[-0.35em] ~\dotfill$

$\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{width}{w}=\sqrt{[-4-(-1)]^2+[-2-(-3)]^2}\implies w=\sqrt{(-4+1)^2+(-2+3)^2} \\\\\\ w=\sqrt{9+1}\implies w=\sqrt{10} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{A=Lw}\implies \sqrt{40}\cdot \sqrt{10}\implies \sqrt{400}\implies \boxed{20}$

7 0

2 years ago

How do i do this ???

Westkost [7]

a peculiar thing about the centroid of a triangle, is that it cuts all the medians in a 2:1 ratio, so JP : PM are on a 2:1 ratio, thus

$\bf JP:PM\qquad 2:1\qquad \cfrac{JP}{PM}=\cfrac{2}{1}\implies \cfrac{27}{PM}=\cfrac{2}{1}\implies \cfrac{27}{2}=PM\\\\-------------------------------\\\\JM=JP+PM\implies JM=27+\cfrac{27}{2}\implies JM=\cfrac{54+27}{2}\\\\\\JM=\cfrac{81}{2}\implies JM=40\frac{1}{2}$