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2 years ago

How does the wavelength of a sound affect the way it moves around corners

1 answer:

8 0

This is the diffraction. The longer the wavelength, the wider it spread. (The greater angle of the sector pattern formed)

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The magnitude of the magnetic field that a long and extremely thin current-carrying wire produces at a distance of 3.0 µm from t

Reil [10]

Answer:

Current (I) = 3 x 10^-2 A

Explanation:

As we know, $B = 4\pi 10^-7 *l/ 2\pi r$

By putting up the values needed from the data...

Current (I) = 2 x 3.14 x (3.0 x 10^-6) (2.0 x 10^-3) / 4 x 3.14 x 10^-7 = 3 x 10^-2 A

6 0

2 years ago

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The average mass of a car in the US is 1.440 x 10^6 g. Express this mass in kg.

wolverine [178]

Answer:

Average mass of acar in the US (in kg) = 1440 kg

Explanation:

Average mass of a car in the US (in g) = 1.440 × 10⁶ g

Mass in kg:

$\rm 1 \: g = {10}^{ - 3} \: kg \\ \\ \rm 1.440 \times 10^6 \ g = 1.440 \times 10^6 \times {10}^{ - 3} \ kg \\ \\ \rm = 1.440 \times 10^{6 - 3} \ kg \\ \\ \rm = 1.440 \times 10^3 \ kg \\ \\ \rm = 1.440 \times 1000 \ kg \\ \\ \rm = 1440 \ kg$

5 0

2 years ago

The diagram shows a swinging pendulum.

pashok25 [27]

Answer:

A. The mechanical energy transforms to thermal energy as the pendulum slows and eventually stops moving.

Explanation:

took the quiz on edge

8 0

2 years ago

Read 2 more answers

Your car burns gasoline as you drive up a large mountain. What energy transformation is the car performing?

Sonja [21]

Your car is performing a transformation of energy of:

Chemical energy to Mechanical energy

The chemical is the gasoline which is then converted to fire as the car runs thus creating the movement of the car which is mechanical energy.

7 0

2 years ago

Read 2 more answers

One mol of a perfect, monatomic gas expands reversibly and isothermally at 300 K from a pressure of 10 atm to a pressure of 2 at

Zolol [24]

Answer:

Explanation:

Given

1 mole of perfect, monoatomic gas

initial Temperature $(T_i)=300 K$

$P_i=10 atm$

$P_f=2 atm$

Work done in iso-thermal process $=P_iV_iln\frac{P_i}{P_f}$

$P_i$ =initial pressure

$P_f$ =Final Pressure

$W=10\times 2.463\times ln\frac{10}{2}=39.64 J$

Since it is a iso-thermal process therefore q=w

Therefore q=39.64 J

(b)if the gas expands by the same amount again isotherm-ally and irreversibly

work done is $=P\Delta V$

$V_1=\frac{RT_1}{P_1}=\frac{1\times 0.0821\times 300}{10}=2.463 L$

$V_2=\frac{RT_2}{P_2}=\frac{1\times 0.0821\times 300}{2}=12.315 L$

$\Delta W=1\times (12.315-2.463)=9.852 J$

$\Delta q=\Delta W=9.852 J$

$\Delta U=0$

8 0

3 years ago