(Distribute the minus sign of the subtrahend in each term.)
= 8r⁶s³ – 9r⁵s⁴ + 3r⁴s⁵ – 2r⁴s⁵ + 5r³s⁶ + 4r⁵s⁴
(Add or subtract like terms.)
= 8r⁶s³ – 5r⁵s⁴ + r⁴s⁵ + 5r³s⁶
(If you want to factor out, then...)
= r³s³ (8r³ – 5r²s + rs² + 5s³)
Using probability concepts, it is found that:
a) 
probability of drawing a card below a 6.
b) 
odds of drawing a card below a 6.
c) We should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.
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- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
Item a:
- In a standard deck, there are 52 cards.
- There are 4 types of cards, each numbered 1 to 13. Thus,
are less than 6.
Then:
probability of drawing a card below a 6.
Item b:
- Converting from probability to odd, it is:
odds of drawing a card below a 6.
Item c:
- The law of large numbers states that with a <u>large number of trials, the percentage of each outcome is close to it's theoretical probability.</u>
- Thus, we should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.
A similar problem is given at brainly.com/question/24233657
1) The graph consists of three horizontal segments, with discontinuities (jumps) at x = 1, x = 2, and x = 3.
A horizontal segment at y = - 2 for the values x = 0 to 1.
A horizontal segment at y = - 1 for values x = 1 to 2
A horizontal segment at y = 0 for values x - 2 to 3.
2) To know whether the end points of a segment are defined by the left or the right values you have to look for the circle at the extreme of the segment: if it is a solid dot, means that the end is included, if is is an open circle (white inside) then the end is not included in that segment.
3) That function is based on the function named integer part because if relates y with the integer part of x.
The integer value function is [x] and it makes correspond y values witht he integer values of x.:
y = 0 witht the integer value of x for x between 0 and 1, excluding 1.
y = 1 with the integer value of x between 1 and 2 (excluding 2)
y = 2 with the integer value of x between 2 and 3 (excluding 3)
y = 3 with the integer value of x between 3 and 4 (excluding 4)
But our function is two units below, so it is [x] - 2
