Were does 9 -4 go on number line

2 answers:

5 0

The integer (9) will be located 9 units from 0 to the right of the number line. The integer (-4) will be located to the left of 0, 4 negative units. All negative numbers should be placed on the left of a number line, however all positive integers are located on the right of the number line.

rosijanka [135]2 years ago

3 0

Draw number line from -5 to 10. .number that line.

Then show a point in 9 and -4

I hope that's what you mean from question

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Lx + 4l = 7 Solve !!

deff fn [24]

Answer:

x1=-11

x2=3

(3,-11)

Step-by-step explanation:

5 0

2 years ago

Please help!!

weqwewe [10]

Answer:

The vertex of the parabola = (-7 , -4)

Step-by-step explanation:

Step(i):-

Given that the parabola y = 4 x² + 56 x +192

y = 4 (x² + 14 x + 48 )

y = 4 ( x² + 2 × 7 (x) + 49-1)

y = 4 ( x² + 2 × 7 (x) + 49)- 4

we apply the formula

(a +b)² = a² + 2ab + b²

y = 4 ( x + 7 )² - 4

Step(ii):-

The general form of the parabola in algebraically

y = a ( x-h)² +k

The equation

y = 4 ( x + 7 )² - 4

y = 4 ( x-(-7))² - 4

The vertex of the parabola (h,k) = (-7 , -4)

Final answer:-

The vertex of the parabola = (-7 , -4)

8 0

2 years ago

Which value of b would make x²+bx-30 factorable? A. -31 B. -17 C. 11 D. 13

dimulka [17.4K]

Answer:

D. 13

Step-by-step explanation:

well since it's a quadratic equation, it can be written in the form of ax²+bx+c=0. So we have a=1, b=b and c= -30. Also the roots are given by the equation-

x= -b± $\sqrt{b^{2}-4ac}$ /2a. So all I did was put the number from the choices which would satisfy the sqrt part and that turned out to be 13 since $\sqrt{13^{2}-4*1*(-30)$ = $\sqrt{289}$ = 17. So b=13.