Answer: 
Step-by-step explanation:
By definition, a relation is a function if and only if each input value has one and only one output value.
For this exercise it is important to remember that thw "Input values" are the values of the variable "x"and the "Output values" are the values of the variable"y".
In this case you have the following function provided in the exercise:
Then, to solve this exercise, you need to follow these steps:
Step 1. You have to substitute 
into the function given.
Step 2. Finally, you must evaluate in order to find the corresponding output value (or the value of the variable "y")
You get that this is:
Answer:
Given the function: y=f(x) = 3x+2
when x=-2 at the beginning of the interval [-2, 5],
then;
y = 3x+2 begins at
y= 3(-2)+2 = -6+2= -4.
and
when x=5 at the end of the interval [-2, 5],
y = 3x+2 ends up at
y= 3(5)+2 = 15+2= 17.
So,
y has changed -4 to 17, which is a change of 17-(-4)= 17+4 = 21
and x has changed from -2 to 5, which is a change of 5-(-2)=5+2=7
So, the average rate of change of y with respect to x over the interval
[-2, 5] is given by ;
=
Therefore, the average rate of change y with respect to x over the interval is, 3
Step-by-step explanation:
The last 2 options are correct
Answer: 3(10^5)
=3*10^5
=3*(10*10*10*10*10)
=300000
This is how you should do It, just when it is squared you should times the number like up here you times 10 times 10 5 times so if you see it you don't times it by 5 you do 10 times 10 times 10 times 10 times 10 like this
You should get it now
Have a good day
Yours,
Nathaniel
Step-by-step explanation:
1. 40
2. 24
3. 7.5
4. 30
5. 22.5
