Answer:
see attached
Step-by-step explanation:
Here's your worksheet with the blanks filled.
__
Of course, you know these log relations:
log(a^b) = b·log(a) . . . . . power property
log(a/b) = log(a) -log(b) . . . . . quotient property
log(x) = log(y) ⇔ x = y . . . . . . . . . equality property
Answer:
64
Step-by-step explanation:
Find the area of both triangles inside the bigger triangle and add them together.
Use the Pythagorean theorem to find the missing length of the leg in the smallest triangle:
a² + b² = c²
8² + b² = 10²
64 + b² = 100
36 = b²
6 = b
Calculate the area of the smaller triangle:
1/2(<em>b</em>x<em>h</em>)
1/2(6 x 8)
1/2(48)
24
Calculate the area of the bigger triangle:
<em>We know that the longer leg is 10 units because we were able to subtract the length of the smaller triangle's leg from 16.</em>
1/2(<em>b</em>x<em>h</em>)
1/2(10 x 8)
1/2(80)
40
Add both areas to find the area of the largest triangle:
40 + 24 = 64
Ratio of large box
96:6
Thus 96/6 = 16
Small box
2*16 = 32
There are 32 candles in the small box.