Answer:
Step-by-step explanation:
Answer:
We accept H₀ we don´t have enough evidence to support that the mean thickness is greater than 41 mm
Step-by-step explanation:
Sample Information:
Results:
41.8
40.9
42.1
41.2
40.5
41.1
42.6
40.6
From the table we get:
sample mean : x = 41.35
sample standard deviation s = 0.698
Hypothesis Test:
Null Hypothesis H₀ x = 41
Alternative Hypothesis Hₐ x > 41
The test is a one-tail test
If significance level is 0.01 and n = 8 we need to use t-student distribution
From t-table α = 0.01 and degree of freedom df = n - 1 df = 8 - 1
df = 7 t(c) = 2.998
To calculate t(s) = ( x - 41 ) / s/√n
t(s) = ( 41.35 - 41 ) / 0.698/√8
t(s) = 0.35 * 2.83/ 0.698
t(s) = 1.419
Comparing t(s) and t(c)
t(s) < t(c)
t(s) is in the acceptance region we accept H₀
Answer:
8
Step-by-step explanation:
Notice:
32 = (8 x 4)
72 = (8 x 9)
Hence,
32 + 72
= (8 x 4) + (8 x 9) (factorize out the 8)
= 8 x (4 + 9)
therefore the musing number is 8
Answer: (110.22, 125.78)
Step-by-step explanation:
The confidence interval for the population mean is given by :-
Given : Sample size = 463
Significance level : 
Critical value : 
We assume that the population is normally distributed.
Now, the 90% confidence interval for the population mean will be :-
Hence, 99% confidence interval for the mean study time of all first-year students = (110.22, 125.78)
