You need to attach the answer choices
ANSWER
EXPLANATION
Parameters given:
Mass of the student, M = 70 kg
Mass of the textbook, m = 1 kg
Distance, r = 1 m
To find the gravitational force acting between the student and the textbook, apply the formula for gravitational force:
where G = gravitational constant
Therefore, the gravitational force acting between the student and the textbook is:
That is the answer.
False. this is just a physical change, not a chemical change.
Answer:
The gravitational potential energy of a squirrel is 53.312 J.
Explanation:
We have,
Mass of a squirrel is 0.68 kg
It is placed at a height of 8 m above the ground.
It is required to find the gravitational potential energy of a squirrel. It is possessed by an object due to its position. Its formula is given by :
So, the gravitational potential energy of a squirrel is 53.312 J.
Answer:
1375J
Explanation:
The gravitational potential/potential energy of the at the top of the tree which is the energy by virtue of its position.
P.E = mgh
mass = m
Acceleration due to gravity = g
height = h
At the top of the tree, the value of h (height) is high resulting in the gravitational potential. When the cat lands on the ground, the value of h is zero, the the gravitational potential would be zero and all the potential energy have been converted to other forms of energy.
Therefore, the total gravitational potential store is equal to the maximum amount of energy that can be transferred which is equal to 1375J.