Answer:
The new volume of the balloon is 38.5 L
Explanation:
Step 1: Data given
Volume at the start = V1 = 35.0 L
Temperature at the start = T1 = 303 Kelvin
Volume by 3pm = TO BE DETERMINED
Temperature by 3pm = 333 Kelvin
<u>Step 2: </u>Calculate the new volume
Charles' gas law says
V1/T1 = V2/T2
V
1 is the initial volume and T1 is the initial temperature
V2 is the final volume and T2 is the final temperature
35 L / 303 Kelvin = V2 / 333 Kelvin
V2 = 35L * 333 Kelvin / 303 Kelvin
V2 = 38.47L ≈ 38.5 L
The new volume of the balloon is 38.5 L
Answer:
C. 1.3 mol
Explanation:
PV = nRT
where P is absolute pressure,
V is volume,
n is number of moles,
R is universal gas constant,
and T is absolute temperature.
Given:
P = 121.59 kPa
V = 31 L
T = 360 K
R = 8.3145 L kPa / mol / K
Find: n
n = PV / (RT)
n = (121.59 kPa × 31 L) / (8.3145 L kPa / mol / K × 360 K)
n = (3769.29 L kPa) / (2993.22 L kPa / mol)
n = 1.26 mol
Round to two significant figures, there are 1.3 moles of gas.