Question

8x-2y^2=12 solve for y

Answer 1

I hope it can help you

Answer 2

8x - 2y² = 12

- 2y² = -8x + 12 subtracted 8x from both sides

y² = 4x - 6 divided both sides by -2

|y| = $\sqrt{4x - 6}$ took square root of both sides

y = +/- $\sqrt{4x - 6}$ eliminated the absolute value