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2 years ago

If 32 % of a is 1.12 then what is the value of a?

Mathematics

1 answer:

alukav5142 [94]2 years ago

7 0

Answer:

4.5 is the value of A

Step-by-step explanation:

do it doing part/whole and cross crossing :)

32/100 because it’s a percentage and 1.12/x. 1.12 times 100 to get 112, and then 32 times x = 32x. your equation right now is 32x = 112, bur we want to get rid of that x, so we are going to divide 112/32 to get the whole of 3.5 for the value of A.

You might be interested in

What are the values of m and 0 in the diagram below?

Lelu [443]

Answer:The correct answer is m= and θ = 30º.

Step-by-step explanation:First, we must form a triangle whose hypotenuse is the radius r=1, its adjacent leg is m, its opposite leg is and the angle is theta.

First, we calculate the angle with theta's breast:

sin (θ) =

where H is the hypotenuse, in this case, the radio.

θ = ()

θ = 30º

Now, we calculate the adjacent leg, which is equal to the x-coordinate of the point:

cos (θ) =

m = cos 30º * H

m =

Have a nice day!

7 0

2 years ago

Plz help and explain ty

mel-nik [20]

4x = 8, so x = 2
5y + 4 = 4, so 5y = 0, so y = 0
(2,0)

8 0

2 years ago

Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.

SCORPION-xisa [38]

Answer:

The solutions are $x=-3,\:x=3$

Step-by-step explanation:

To factor this cubic polynomial $x^3+3x^2-9x-27$ you must:

Group the polynomial into two sections

$x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)$

Factor out -9 from $(-9x-27)$

$(-9x-27)=-9\left(x+3\right)$

Factor out $x^2$ from $(x^3+3x^2)$

$(x^3+3x^2)=x^2\left(x+3\right)$

$x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)$

Factor out common term $x+3$

$-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)$

$x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)$

Factor $x^2-9$

$x^2-9=\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0$

Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

$x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}$

The solutions are

$x=-3,\:x=3$

3 0

2 years ago

Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x

Savatey [412]

The polynomial remainder theorem states that the remainder upon dividing a polynomial $p(x)$ by $x-c$ is the same as the value of $p(c)$ , so to find $p(-10)$ you need to find the remainder upon dividing

$\dfrac{2x^3+14x^2-58x}{x+10}$

You have

..... | 2 ... 14 ... -58
-10 | ... -20 ... 60
--------------------------
..... | 2 ... -6 .... 2

So the quotient and remainder upon dividing is

$\dfrac{2x^3+14x^2-58x}{x+10}=2x-6+\dfrac2{x+10}$

with a remainder of 2, which means $p(-10)=2$ .

5 0

2 years ago

3( 5x+10x -2)=<br> I NEED HELP

Anit [1.1K]

Answer:

45x-6

Step-by-step explanation:

math

way

5 0

2 years ago

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