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2 years ago

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Four conditions which cause a metathesis reaction to occur?

1 answer:

zubka84 [21]2 years ago

4 0

Metathesis is a type of reaction in which the cations and anions exchange partners. this reaction is also called double replacement. Metathesis reactions are driven by the formation of a product .this reaction is classified into three different categories: formation of precipitate, f<span>ormation of a Weak or Non-electrolyte and production of the gas.</span>

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You dissolve 14 g of Mg(NO3)2 in water and dilute to

mart [117]

Answer:

0.127M

Explanation:

Molarity of a solution = number of moles (n) ÷ volume (V)

Molar mass of Mg(NO3)2 = 24 + (14 + 16(3)}2

= 24 + {14 + 48}2

= 24 + 124

= 148g/mol

Using the formula, mole = mass/molar mass, to convert mass of Mg(NO3)2 to mole

mole = 14g ÷ 148g/mol

mole = 0.095mol

Volume = 750mL = 750/1000 = 0.75L

Molarity = 0.095mol ÷ 0.75L

Molarity = 0.127M

3 0

2 years ago

N2H4+H2O2 ——> N2+H2O coefficient

const2013 [10]

Answer:

N2H4 + 2H2O2 ---->N2 + 4H2O

Explanation:

N=2 N=2

H=6 ->8 H=2 ->8

O=2 -> 4 O=1 -> 4

Add coefficients to hydrogen peroxide on the left and water on the right, so that there is an equal number of hydrogens and oxygens.

3 0

2 years ago

The process of splitting and Atom into two lighters atoms is called?

natima [27]

<span>The process of splitting and Atom into two lighters atoms is called </span> $Nuclear Fission$

5 0

2 years ago

What is the coefficient of the H2O in the balanced chemical

Ivahew [28]

Answer:

Al2O3 + H2SO4 = Al2(SO4)3 + H2O

Explanation:

4 0

2 years ago

How many hydrogen atoms are in 35.0 grams of hydrogen gas? How many hydrogen atoms are in 35.0 grams of hydrogen gas? 4.25 × 102

Ede4ka [16]

Answer: $2.12\times 10^{25}$ atoms of hydrogen are there in

35.0 grams of hydrogen gas.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{35.0g}{2g/mol}=17.5moles$

1 mole of hydrogen $(H_2)$ = $2\times 6.023\times 10^{23}=12.05\times 10^{23}$ atoms

17.5 mole of hydrogen $(H_2)$ = $\frac{12.05\times 10^{23}}{1}\times 17.5=2.12\times 10^{25}$ atoms

There are $2.12\times 10^{25}$ atoms of hydrogen are there in

35.0 grams of hydrogen gas.

8 0

2 years ago