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Makovka662 [10]

2 years ago

12

These are the first six terms of a sequence with a1= - 3: - 3, 8, 19, 30, 41, 52, … Find a recursive formula for this sequence t

hat is valid for n>1. Write your answer in simplest form.

1 answer:

ad-work [718]2 years ago

6 0

Answer:

$a(n+1)=a(n)+11$

Step-by-step explanation:

The difference between two consecutive elements is 11.

$8=-3+11\\19=8+11\\30=19+11\\41=30+11\\52=41+11\\$

Hence $a(n+1)=a(n)+11$

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