Answer: i think (4n+1)^2(4n-1)^2 isnt a multiple of 8 for all integers of n because:
(4n + 1)²(4n - 1)²
= [(4n + 1)(4n - 1)]²
= (16n² - 1)²
= 16².n².n² - 2.16.n² + 1
= 8n²(32n² - 4) + 1
can see 8n²(32n² - 4) is a multiple of 8 but 1 isnt a multiple of 8
=> (4n + 1)²(4n - 1)² isnt a multiple of 8 for all integers of n.
Step-by-step explanation:
Answer:
n = ⅜
Step-by-step explanation:
Answer:
Either (approximately ) or (approximately .)
Step-by-step explanation:
Let denote the first term of this geometric series, and let denote the common ratio of this geometric series.
The first five terms of this series would be:
First equation:
.
Second equation:
.
Rewrite and simplify the first equation.
.
Therefore, the first equation becomes:
..
Similarly, rewrite and simplify the second equation:
.
Therefore, the second equation becomes:
.
Take the quotient between these two equations:
.
Simplify and solve for :
.
.
Either or .
Assume that . Substitute back to either of the two original equations to show that .
Calculate the sum of the first five terms:
.
Similarly, assume that . Substitute back to either of the two original equations to show that .
Calculate the sum of the first five terms:
.