Answer:
Volume of acid, Va=250mL; Volume of quinine,Vb=20mL; Molarity of acid, Ma=0.05M.
Molar mass of acid= H2+S+O4= 2+32+(16X4)= 2+32+64=98g
Concentration of acid, Ca= Molar mass of acid/ Ma =98/0.05=1960g/mol
Explanation: To calculate concentration of quinine, Cb is as follow
Va*Ca=Vb*Cb
∴ Cb=Va*Ca/Vb =250*1960/20 =24500g/mol
Answer:
C) 4.24 x
Explanation:
E = Δm
Δm = 0.0284 x 1.66 x kg = 4.714xkg
putting value in above equation
E = 4.714xkg x (3x = 4.24 x
Answer:
It is always twice the value of the actual yield.
Explanation: