Answer:
There are 29.4 grams of oxygen in the container
Explanation:
<u>Step 1: </u>Data given
Volume = 20.0 L
Pressure = 845 mmHg
Temperature = 22.0 °C
Molar mass of O2 = 32 g/mol
<u>Step 2:</u> Ideal gas law
p*V = n*R*T
⇒ p = the pressure of the gas = 845 mmHg = 1.11184
⇒ V = the volume of the gas = 20.0 L
⇒ n = the number of moles = TO BE DETERMINED
⇒R = the gasconstant = 0.08206 L*atm/K*mol
⇒ T = the temperature = 22°C + 273 = 295 Kelvin
n = (p*V)/(R*T)
n = (1.11184*20.0)/(0.08206*295)
n = 0.9186 moles
<u>Step 3:</u> Calculate mass of NO2
Mass of O2 = Moles O2 * Molar mass O2
Mass of O2 = 0.9186 moles * 32 g/mol
Mass of O2 = 29.4 grams
There are 29.4 grams of oxygen in the container
Answer:
Explanation:
Hello there!
In this case, according to the Gay-Lussac's gas law, which illustrates the pressure-temperature behavior as a directly proportional relationship:
We can solve for the final pressure as shown below:
Thus, we plug in the initial pressure and temperature and final temperature to obtain:
Which is not among the choices.
Regards!
A i believe hope it helps
The correct answer is C, too deep in the Earth to collect. Hope this helps!
According to Newton's third law, forces come in pairs. There is action-reaction force and an equal (in size - action force) and opposite in direction (reaction force).
<u>Explanation:</u>
On the off chance, when item A applies a force on item B, at that point item B must apply a force of equivalent size and inverse bearing back on object A. This Newton's third law speaks to a specific balance in nature: forces consistently happen two by two.
And, one body can't apply a force on another without encountering a force itself. Now and again, allude to this law freely as activity response, where the force applied is the activity and the force experienced as a result is the response.