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2 years ago

find an equation of the line passing through the point (5 4) and parallel to the line whose equation is y= 2x-6

Mathematics

1 answer:

yKpoI14uk [10]2 years ago

3 0

Answer:

$y = 2x - 6$

Step-by-step explanation:

Given

Equation: $y = 2x - 6$

Required

Determine the equation of Point: (5,4)

First, we need to determine the slope of $y = 2x - 6$

The general form of an equation is $y = mx + b$

Where m represents the slope;

Hence; $m =2$

Since the equation and the point are parallel. then they have the same slope (m).

$m = 2$

Next, is to determine the equation of the point, using the following formula:

$m = \frac{y - y_1}{x - x_1}$

Where

$(x_1,y_1) = (5,4)$

So, the equation becomes

$2 = \frac{y - 4}{x - 5}$

Cross Multiply

$y - 4 = 2(x - 5)$

Open Bracket

$y - 4 = 2x - 10$

Make y the subject of formula

$y = 2x - 10 + 4$

$y = 2x - 6$

Hence, the equation is $y = 2x - 6$

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