The answer is A: 4. This is easy once you know the order of operations, aka PEMDAS. Parentheses, exponents, multiplication/division, and addition/subtraction.

3 0

2 years ago

In a certain board game, a 12-sided number cube

alexandr1967 [171]

Answer:

4/27 ezzzzzzzzzzzzzzzzzzzz

8 0

1 year ago

Find all the zeros of the equation

lapo4ka [179]

Divide both sides by -3, and replace $x^2$ with $y$ . Then

$-3x^4+27x^2+1200=0\iff y^2-9y-400=0$

Factorize the quadratic in $y$ to get

$y^2-9y-400=(y+16)(y-25)=0\implies y=-16,y=25$

which in turn means

$x^2=-16,x^2=25$

But $x^2\ge0$ for all real $x$ , so we can ignore the first solution. This leaves us with

$x^2=25\implies x=\pm\sqrt{25}=\pm5$

If we allow for any complex solution, then we can continue with the solution we ignored:

$x^2=-16\implies x=\pm\sqrt{-16}=\pm i\sqrt{16}=\pm4i$

6 0

3 years ago