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2 years ago

How many moles of calcium are there in 5.74 x 1022 atoms of calcium?

Chemistry

1 answer:

igor_vitrenko [27]2 years ago

6 0

Answer:

0.095 moles of Calcium is there in 5.74 x 1022 atoms of calcium.

Explanation:

As we know, 6.023*10^23 atoms of an element is equal to its atomic weight.

And, 6.023*10^23 atoms of an element is also equal to 1 mole of the element.

We have,

6.023*10^23 atoms of element calcium equals to 1 mole of Calcium
5.74*10^22 atoms of element calcium equals to

(1/(6.023*10^.23)) * 5.74*10^22 moles of calcium

Therefore,

5.74 x 1022 atoms of calcium= 0.095 moles of calcium.

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<h3>Explanation</h3>

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The "III" in the name "chromium (III) nitrate" is a Roman Numeral. It indicates that the oxidation state of Cr in chromium (III) nitrate is +3. The Cr in that compound will exist as $\text{Cr}^{3+}$ . Similarly, each $\text{Cr}^{3+}$ will pair up with three ${\text{NO}_3}^{-}$ ions. The formula for chromium (III) nitrate will be $\text{Cr}(\text{NO}_3})_3$ . Each formula unit of chromium (III) nitrate will contain one ${\text{NO}_3}^{-}$ ion and three ${\text{NO}_3}^{-}$ ions.

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