Answer:
0.0195 m
Explanation:
= density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³
= diameter of hockey puck = 13 cm = 0.13 m
= height of hockey puck = 2.8 cm = 0.028 m
= density of mercury = 13.6 gcm⁻³ = 13600 kgm³
= depth of puck below surface of mercury
According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck
Weight of mercury displaced = Weight of puck
<span>C. They decay at a predictable rate. IE carbon 14 decay to carbon 12 to understand how long ago something was alive.</span>
Answer:
Explanation:
Distance travelled = 600 - 500 = 100 m
Time taken = 9:03:25 a.m.- 9:03 :05 a.m.
= 20 s
average speed = distance / time taken
= 100 / 20 m /s
= 5 m /s
Answer:
Not including a sedimentary cover of variable thickness and composition, the oceanic crust consists of three layers: (1) a relatively thin uppermost volcanic layer of basaltic lavas known as mid-ocean ridge basalts (MORB) erupted on the seafloor; (2) a thicker layer of more coarsely crystalline, intrusive basaltic
Answer:
4.44 i + 11.11 j , 11.96 m/s
Explanation:
m1 = 0.2 kg, v1 = 10 m/s along X axis, v1 = 10 i
m2 = 0.25 kg, v2 = 20 m/s along north, v2 = 20 j
After collision they stick together and let they move with velocity v.
Use the conservation of momentum
m1 x v1 + m2 x v2 = (m1 + m2) x v
0.2 x (10 i) + 0.25 x (20 j) = (0.2 + 0.25) x v
2i + 5j = 0.45 v
v = 4.44 i + 11.11 j
magnitude of velocity = = 11.96 m/s
Thus, the velocity of 0.250 kg hockey puck is 4.44 i + 11.11 j metre per second and the magnitude of velocity is 11.96 m/s.