Answer:
Step-by-step explanation:
I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.
..
let quarters be x
dimes = x+2
...
dimes + quarters = x+x+2=2x+2
...
nickels = 30-(2x+2)
...
5(30-(2x+2))+10(x+2)+25x=460
5(30-2x-2)+10x+20+25x=460
150-10x-10+10x+20+25x=460
160+25x=460
-160
25x=460-160
25x=300
/25
x=300/25
x=12 ---- quarters
x+2= 12+2=14 dimes
30-(2x+2)=4 nickels
...
check
4*5+14*10+12*25=20+140+300=460
Answer: 3935376
Step-by-step explanation: 3927283+8093
3935376
Answer:
The range is y ≥ -1
Step-by-step explanation:
∵ f(x) = (x - 4)(x - 2)
∴ f(x) = x² - 2x - 4x + 8
∴ f(x) = x² - 6x + 8 ⇒ quadratic function (ax² + bx + c) represented by
parabola graphically
∵ a = 1 , b = -6 , c = 8
∴ x-coordinate of its vertex = -b/2a = -(-6)/2×1 = 3
∴ f(3) = (3)² - 6(3) + 8 = -1
∵ a is positive ⇒ the curve has minimum point and it's open upward
∴ the minimum point is (3 , -1)
∴ The range is y ≥ -1 ⇒ because the minimum value is -1
Answer: 18.75 for each girl
Step-by-step explanation:
First you take the unit rate 2.50 multiply by 5.
2.50 x 5 = 12.50
12.50 x 3 = 37.50
37.50 / 2 = 18.75
The difference between the sum of all eight positive integral divisors of 66 and the sum of all eight positive integral divisors of 70 is zero.
<h3>How to find the difference between the integral divisors?</h3>
First let's find the integral divisors. We can write 66 as a product of prime numbers as:
66 = 33*2 = 2*3*11
Then the integral divisors of 66 are:
2
3
11
2*3 = 6
2*11 = 22
3*11 = 33
1 (trivially)
66 (trivially)
The sum gives:
2 + 3 + 11 + 6 + 22 +33 + 1 + 66 = 144
For 70 we have:
70 = 7*10 = 2*5*7
Then the integral divisors are:
1
70
2
5
7
2*5 = 10
2*7 = 14
5*7 = 35
The sum gives:
1 + 70 + 2 +5 + 7 + 10 + 14 + 35 = 144
Then the difference between these two sums is:
144 - 144 = 0
If you want to learn more about integral divisors:
brainly.com/question/4785696
#SPJ1
