Answer:
74
Step-by-step explanation:
Say that arc JL going through M is arc E and JL going the other way is arc D
For the angle formed by two tangents, K=(1/2)(E-D)
64=E-D
Furthermore, angle K and central angle JCL (facing toward K) are supplementary, so 180-K=JCL=180-32=148
Thus, as the angles around angle C add up to 360, angle JCL (facing toward M) is 360-148=32+180=212
E is then 212
64=212-D
212-64=D=148
Thus, as JML is an inscribed angle, M=1/2(D)=1/2(148)=74
Answer:
Step-by-step explanation:
Step-by-step explanation:
LHS= sin 3x/sin x - cos 3x/cosx
Taking LCM,
<u>=</u><u>sin3xcosx- cos3xsinx</u>
sinxcosx
<u>=</u><u>sin(3x-x)</u>
sinxcosx
= <u>2sin2x</u>
2sinxcosx
=<u> </u><u>2sin2x</u><u> </u>
sin2x
=2
= RHS.
Proved.
0.25 times r added to 0.6 times 6