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2 years ago

What’s the critical points for this question?

Mathematics

1 answer:

V125BC [204]2 years ago

6 0

The critical point is (0,316)(-6,-116)

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You know of a relative who is addicted to pain killers. Due to his history, 2.3g of Tylenol per day is dangerous. He takes 200 m

Nezavi [6.7K]

Answer: So, your relative takes N tablets each 6 hours. a day has 24 hours, and 24/6 = 4, so he takes N tablets 4 times per day, so he takes 4*N tablets.

each tablet has 200mg, and 2.3 g (or 2300 mg) is toxic.

this means that 4*N*200mg must be less than 2300, if we are seeking for the maximum N possible, then:

4*N*200mg = 2300mg

4*N = 2300/200 = 11.5

N = 11.5/4 = 2.87

if you round up this number, you will end up taking more than 2.3g of tylenol per day, this implies that N must be equal to 2.

So your relative needs to take maximum 2 tablets per day.

7 0

2 years ago

A grocery delivery service has 22 members. Each member pays monthly dues of $12.80

slava [35]

Answer:

Step-by-step explanation:

If 9 members paid on the first day, this means they did not pay on the third day

The remaining people (everyone but the 9) paid on the third day

Therefore we must subtract to find out how many members paid on the third day

22 - 9 = 13

Each of the 13 members paid $12.80 which means we must multiply

13 × 12.80 = 166.40

In total, the grocery store collected $166.40 on the third day of the month

3 0

2 years ago

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Will mark brainliest!<br> (problem below)

Vlad [161]

Answer:

Joe

Hope this helps!

4 0

2 years ago

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Can you help me with 6?

Paul [167]

Answer:

Less then

Step-by-step explanation:

When you dived by a decimal the answer decreases.

3 0

2 years ago

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What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36

GREYUIT [131]

ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

$f(x) = {x}^{4} - 13 {x}^{2} + 36$

To find the real roots, we equate the function to zero to obtain;

${x}^{4} - 13 {x}^{2} + 36 = 0$

We can solve this equation as a quadratic equation in
${x}^{2}.$

Thus we rewrite the equation as,

$({x}^{2})^{2} - 13 {x}^{2} + 36 = 0$

We split the middle term to get,

$({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.$

We factor to get,

${x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0$

We factor to get,

$( {x}^{2} - 9)( {x}^{2} - 4) = 0$

Either

${x}^{2} - 9 = 0$
or

${x}^{2} - 4 = 0$

$x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}$
$x = \pm3 \: or \: x = \pm2$

$x=-3,-2,2,3$

The correct answer is A

5 0

3 years ago

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