An animal shelter spends $1.00 per day to care for each cat and $8.00 per day to care for each dog. Mackenzie noticed that the s
2 answers:
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Answer:
option (a) $6,240
Step-by-step explanation:
Given:
Purchasing cost of the equipment = $82,000
Estimated life = 5 years
Salvage value = $4,000
Revised expected life = 8 years
Now,
Depreciation per year =
therefore,
The accumulated Depreciation at the beginning of year 4
= Annual depreciation × years passed
= 15,600 × 3
= $46,800
Thus,
The book value at the beginning of year 4
= Purchasing cost - Depreciation
= $82,000 - $46,800
= $35,200
Now,
The remaining life = Revised estimated life - Years passed
= 8 - 3
= 5 years
therefore,
Depreciation expense =
=
= $6,240
Hence,
The correct answer is option (a) $6,240
The probability that the aircraft is overloaded is 97.98%, which means the pilot should take the action.
In a Normal distribution with mean ц and standard deviation σ, the z-score of a measure x is given by:
Z = X-ц / σ
· It measures how many standard deviations the measure is from the mean.
· After finding Z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
· By the Central Limit Theorem, the sampling distribution of sample means of the size n has standard deviation σ
σ = σ /
σ is standard deviation
n is the sample size.
Given that the mean and the standard deviation of the population is 176.1 lb and 35.4 respectively.
⇒ ц = 176.1 and σ = 35.4
For a sample of 43 passengers, we have
n = 43
σ =
σ = 5.398
Z = X-ц / σ
Z =
Z = -2.05 has p- value of 0.9798
The probability that the aircraft is loaded is
1 - p-value of Z
1 - 0.0202 = 0.9798
The probability that the aircraft is overloaded is 97.98%
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