To find the hypotenuse of a 45 45 90 triangle, multiply the leg by sq root (2)
8 * sqrt(2) = 8 *
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1.4142135624
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=
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11.313708499
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Source:
http://www.1728.org/trig2.htm
13. 39
14. 2(x+4)
15. 24
16. 11(x+5)
17. 6(4x+3y)
18. 8(2x+10y)
19. 5(2x+3)
Hope this helped☺☺
Answer:
768 bugs
Step-by-step explanation:
You can rewrite this problem as a function as time where the bug population is f(x), and x is the number of days since the start.
f(x)=6*2^(x/5)
Here, the 6 represents the number of bugs that you start with, the two shows that they double every day, and the /5 shows that they double every 5 days.
By plugging in 35, you get 6*2^7, which is 768.
I’m not sure about number 1 but the answer for number 2 is
-4 1/2, -4.2, -4, ,0, 4
Answer:
5
Step-by-step explanation:
a polynomial has one quadratic factor and 3 linear factors. One of the linear factors has multiplicity two. What is the degree of the polynomial
A polynomial with one quadratic obtains the forms ( ax² +bx +c ) with 3 linear factors.
Suppose the three linear fractions are :
(x- P) (x-Q) (x- R)
∴
The polynomial = ( ax² +bx +c )(x- P) (x-Q) (x- R)
By factorization, the highest degree of the polynomial = 5