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2 years ago

Solutions for the linear systems 5x-2y=-48 and 2x+3y=-23

Mathematics

1 answer:

Serga [27]2 years ago

7 0

5x-2y=-48>>>> Y=24-5/2X

2x+3y=-23>>>> Y=-8-2/3X

Hope this helps!

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What is the equation of the line shown in this graph

prisoha [69]

Slope = (2+4)/(1-4) = 6/-3 = -2
passing thru (1.2)
y = mx + b
b = y - mx
b = 2 - (-2)(1)
b = 2 + 2
b = 4

equation
y = -2x + 4

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2 years ago

Jack and Jill are brother and sister. Jack rakes the yard in 5 hours and Jill rakes the yeard in 8 hours. Mom says to rake the y

SVETLANKA909090 [29]

Given that <span>Jack rakes the yard in 5 hours and Jill rakes the yeard in 8 hours. Let the amount of time that it takes them to rake the yard together be t, then:

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2 years ago

What is the simplified form of √144x^36

Nadusha1986 [10]

Answer:

The simplified form of $\sqrt{144x^{36}}$ is $12x^{18}$

Step-by-step explanation:

Given : $\sqrt{144x^{36}}$

We have to write the simplified form of $\sqrt{144x^{36}}$

Consider the given expression $\sqrt{144x^{36}}$

We know $\sqrt{144}=12$

and $\sqrt{x^{36}}=\sqrt{x^{18}\cdot x^{18}}$

Thus,

$\sqrt{144x^{36}}=\sqrt{12^2\cdot (x^{18})^2}$

Simplify, we have,

$=\sqrt{12^2\cdot (x^{18})^2}=12x^{18}$

Thus, The simplified form of $\sqrt{144x^{36}}$ is $12x^{18}$

6 0

2 years ago

Read 2 more answers

Find all solutions to the equation in the interval [0, 2π). cos 2x - cos x = 0

Jlenok [28]

This is the concept of algebra, to solve the expression we proceed as follows;
cos 2x-cosx=0
cos 2x=cosx
but:
cos 2x+1=2(cos^2x)
thereore;
from:
cos 2x=cos x
adding 1 on both sides we get:
cos 2x+1=cos x+1
2(cos^2x)=cosx+1
suppose;
cos x=a
thus;
2a^2=a+1
a^2-1/2a-1/2=0
solving the above quadratic we get:
a=-0.5 and a=1
when a=-0.5
cosx=-0.5
x=120=2/3π
when x=1
cos x=1
x=0
the answer is:
x=0 or x=2/3π

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2 years ago

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Find the area of a rectangle with a length of 5 1/3 inches and a width of 2/3 inch

neonofarm [45]

Step-by-step explanation:

$length \: of \: rectangle \\ l = 5 \frac{1}{3} \: inches = \frac{16}{3} \:inches \\ \\ width \: of \: rectangle \: \\ w = \frac{2}{3} \: inch \\ \\ area \: of \: rectangle \\ = l \times w \\ \\ = \frac{16}{3} \times \frac{2}{3} \\ \\ = \frac{32}{9} \\ \\ \red{ \boxed{ \therefore area \: of \: rectangle = 3 \frac{5}{9} \: {inch}^{2} }}$

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2 years ago