Question

The escape velocity of a rocket from the earth is 11kms^-1. Taking the acceleration due to gravity as 9.8ms^-2, calculate the radius of the earth.

Answer 1

Answer:

6.37*10^6 m

Explanation:

We know that,

g = GM/R²

values given to us

acceleration due to gravity = g = 9.8 m/s²

Mass of the earth is= 6.4*10^24

G = 6.67*$10^{-11}$

implementing

9.8 = 6.67*10^-11 * 6*10^24/R^2

9.8 = 40.02 * 10^13/ R^2

R^2 = 4002/98 * 10^12

R^2 = 40.83* 10^12

R= 6.37*10^6 m   (approximately)