Answer:
32% decrease
Step-by-step explanation:
Solution:
Calculate percentage change
from V1 = 25 to V2 = 17
so:
4m≥m+9>-9+4m Please answer urgent
1 answer:
Next time, please include the instructions.
This inequality could be broken into two parts:
4m
m + 9 AND m + 9 > -9 + 4m
Focus first on the inequality m + 9 > -9 + 4m. subtract m from both sides, obtaining:
9 > -9 + 3m. Next, add 9 to both sides, obtaining: 18>3m, or m<6
Last step: Determine whether the inequality <span>4m≥m+9 is true if m<6.</span>
This inequality could be broken into two parts:
4m
Focus first on the inequality m + 9 > -9 + 4m. subtract m from both sides, obtaining:
9 > -9 + 3m. Next, add 9 to both sides, obtaining: 18>3m, or m<6
Last step: Determine whether the inequality <span>4m≥m+9 is true if m<6.</span>
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Answer:
a) There are 9 outcomes.
b) **i have attached the tree diagram**
c) 1/9
d) 1/9
Step-by-step explanation:
Both events (choosing a shirt and choosing pants) are not mutually exclusive (disjoint). Meaning that both events can occur at the same time.
a) For a sequence of two events in which the first event can occur <em>m</em> ways and the second event can occur <em>n</em> ways, the events together can occur a total of <em>m</em> • <em>n</em> ways. So for this problem, you would do 3 • 3 which equals 9.
b) **tree diagram is attached**
c) Because there are two different events occurring (choosing a shirt and choosing pants) you need to multiply using the Multiplication Rule for Independent Events : P(A and B) = P(A) * P(B)
The probability of event A occurring (choosing a red shirt) is 1/3 and the probability of event B occurring (choosing brown pants) is also 1/3.
1/3 * 1/3 = 1/9
d) You would do the same thing here as part c.
The probability of event A occurring (choosing a blue shirt) is 1/3 and the probability of event B occurring (choosing blue pants) is again 1/3.
1/3 * 1/3 = 1/9
I hope this was helpful!! :)
