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2 years ago

The graph of the function g(x) is a transformation of the parent function f(x)=x^2

Mathematics

1 answer:

My name is Ann [436]2 years ago

8 0

G(x)=(x+3)2 we must find x? so x+3=0 x=-3 we transformation -3 on left

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2. There are 1500 candies in a candy dish. Each day half of the candy is taken out.

katen-ka-za [31]

Answer:

so easy and obvious dude

Step-by-step explanation:

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2 years ago

Mae Ling earns a weekly salary of $365 plus a 7.5% commission on sales at a gift shop. How much would she make in a work week if

Alexus [3.1K]

Answer:

$732.5

Step-by-step explanation:

Mae Ling earns a weekly salary of $365 which means salary per week is $365

Then plus a 7.5% commission on sales at a gift shop if she sold $4,900 worth of merchandise, which means additional

(0.075×4900)=367.5

The total she make will be

367.5+365

=$732.5

Therefore,she will make $732.5 in a work week if she sold $4,900 worth of merchandise

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2 years ago

What characteristics are true for all linear, exponential and quadratic functions

sweet-ann [11.9K]

Answer:

D) The domain of the function is all real numbers

Step-by-step explanation:

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2 years ago

Andrew rode his bike at a constant speed.He rode 1mile in 5 minutes.

Rudiy27

Answer:

Step-by-step explanation

The answer is three because if you did the tree method you will have the same exact answer

3 0

2 years ago

Read 2 more answers

Verify that this trigonometric equation is an identity?

Vlada [557]

$\cot x\sec^4 x=\cot x+2\tan x+\tan^3x\\\\L=\dfrac{\cos x}{\sin x}\cdot\dfrac{1}{\cos^4x}=\dfrac{1}{\sin x}\cdot\dfrac{1}{\cos^3x}=\dfrac{1}{\sin x\cos^3x}\\\\R=\dfrac{\cos x}{\sin x}+2\cdot\dfrac{\sin x}{\cos x}+\dfrac{\sin^3x}{\cos^3x}\\\\=\dfrac{\cos x\cos^3x}{\sin x\cos^3x}+\dfrac{2\sin x\cos^2x}{\cos x\sin x\cos^2x}+\dfrac{\sin^3x\sin x}{\cos^3x\sin x}\\\\=\dfrac{\cos^4x+2\sin^2x\cos^2x+\sin^4x}{\sin x\cos^3x}\\\\=\dfrac{(\cos^2x)^2+2\sin^2x\cos^2x+(\sin^2x)^2}{\sin x\cos^3x}$

$=\dfrac{(\cos^2x+\sin^2x)^2}{\sin x\cos^3x}=\dfrac{1}{\sin x\cos^3x}=L\\\\Used:\\\tan(a)=\dfrac{\sin(a)}{\cos(a)}\\\cot(a)=\dfrac{\cos(a)}{\sin(a)}\\\sec(a)=\dfrac{1}{\cos(a)}\\\sin^2a+\cos^2a=1\\(a+b)^2=a^2+2ab+b^2$

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2 years ago