A sound wave leaves the loudspeaker. As it travels, it experiences a temporary increase in wavelength and then returns to its original wavelength. The sound wave traveled through a helium balloon (helium is less dense than air could explain this change in wavelength
The pattern of disruption brought on by energy moving away from the sound source is known as a sound wave. Longitudinal waves are what makeup sound. This indicates that the direction of energy wave propagation and particle vibrational propagation are parallel. The atoms oscillate when they are put into vibration.
A high-pressure and a low-pressure zone are created in the medium as a result of this constant back and forth action. Compressions and rarefactions, respectively, are terms used to describe these high- and low-pressure zones. The sound waves go from one medium to another as a result of these regions being transmitted to the surrounding media.
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Answer:
it have two answers a and c
Explanation:
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Answer:
Explanation:
Given that,
Frequency of a radio antenna is 1 MHz
Power, P = 21 kW
We need to find the the waves intensity 25 km from the antenna
. The object emits intenisty evenly in all direction. It can be given by :
So, the wave intensity 25 km from the antenna is .
Answer:
The answer is 20727w
Explanation:
The formula is below;
P = d r^2 v^3 *efficiency
In the question, it is stated that the registration ignores efficiency so we are going to ignore efficiency in the equation and use it this way;
P = d r^2 * v^3
d =4.3, r = 1.59, v =n 12.4
Therefore, P = 4.3 X 1.59^2 X 12.4^3 = 20727W