Admitting that the "a" is a capital A for normal pigmentation and "d" is a capital D for dimpled chin, meaning that these are the dominant traits, the fraction expected to be albino with a non-dimpled chin is of 1/16.
When two heterozygous are crossed and two characteristics are being analysed, the offspring quantity that will possess the two recessive traits can be represented by 1/16. This is easily confirmed when a Punnett square is made. Considering that both parents were heterozygous, on both sides of the crossing in the Punnett square, you would have the following alleles' combination: AD, Ad, aD, and ad. The offspring that would be homozygous recessive (aadd) would correspond to only 1/16.
Answer: Cell number one is an hypotonic solution, cell number two is an isotonic solution, and cell three is an hypertonic solution.
Explanation:
Cell number one which is a 98% water content is added the 100% water solution, water moves from low to high concentration. Therefore, the water moves from the solution into the cell, which is hypotonic.
Cell number two which is a 98% water content added with a 98% water solution. These two solutions are equal to one another, so the water does not move. This is isotonic.
Cell number three which is a 98% water content added with a 80% water solution. Water moves from high to low concentrations, so water moves from the cell to the solution. The water leaves the cell, which is an hypertonic.
You can make a table with each sun/star and plot them by color/heat. I hope this helps!
