Graphs of functions on the interval [−4, 4] are depicted below. For each function, find:

Mathematics

1 answer:

DENIUS [597]2 years ago

4 0

Answer:

a) The domain is the set of the possible values of x.

In the graph, we can see that x goes from - 4 to 4

So the domain is: D = x∈ {-4, 4)

b) The zeros are the points where the graph cuts the x-axis.

Those values are:

x = -2

x = 0

x = 2.

c) The graph is positive if it is above the x-axis and it is negative if it is below the x-axis.

in the interval {-4,0} the graph is bellow the x-axis, so in this interval the function is negative.

in the interval {0, 2} the graph is above the x-axis, so in this interval the function is positive.

in the interval {2, 4} the graph is bellow the x-axis, so in this interval the function is negative.

You might be interested in

Use the formula A=2πrh to find the area of the curved surface of each of the cylinders below. (Express your answers correct to 1

shusha [124]

Answer:

here,

A=2×22÷7×17/2×21

A=22×17×3

A=1122 sq.cm

3 0

2 years ago

Identity each pair of angles

ElenaW [278]

Do you have a protractor? You’ll need one measure the angles.

5 0

3 years ago

Read 2 more answers

What if a fence painting competition allowed pairs to compete? If Ben Rogers can paint the fence in 8 min on his own and Johnny

Delvig [45]

Answer:

I'm confused on what it's asking

Step-by-step explanation:

7 0

2 years ago

Given the graph below, which of the following statements is true?

Nesterboy [21]

To be a function, it has to pass the vertical line test, which means a vertical line drawn anywhere in the graph should cut the graph only once, not more.

To be a one-to-one function, it has to pass the vertical line test as well as the horizontal line test, which means that a horizontal line drawn anywhere in the graph should cut the graph only once, not more.

Of course, it passes the vertical line test, so its a function.

Does it pass the horizontal line test? NO! As shown in the attached picture, the blue line (horizontal line) cuts the graph at 3 places. We therefore eliminate choices A and B. We can eliminate choice C because nowhere is it required a function to pass through the origin for it to be one-to-one. Hence, the answer is D (blue line shows this).

ANSWER: D