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2 years ago

HELP please!! “Find the volume of the sphere rounded to the nearest hundredth

Mathematics

1 answer:

zvonat [6]2 years ago

5 0

Answer:

904.32 cm^3

Step-by-step explanation:

The formula for the volume of a sphere is V=4/3πr³. Since r is given, we can plug that in for r. I'm assuming that we are using 3.14 for pi, so when we plug in all the values in the equation we get V = 4/3*3.14*6³, which solves out to 904.32.

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What is the quotient (3x^3 10x^2 10x 4) divided by (x 2)?

lozanna [386]

Answer:

3x^2 + 16x + 42

3x^2 + 4x + 2

3x^2 – 16x + 42

3x^2 – 4x + 2

Step-by-step explanation:

3 0

2 years ago

Sandeep has twice as much as sonia. together they have rs 150. how much does sonia have

Inga [223]

let sonia has the (x)

Sandeep would have twice as much as Sonia so (2x)

together they'd have 150.

so, x+2x=150

solve for X

3x=150

X=150/3

So x=50 is what Sonia has,

and Sandeep would have 2(50) =100

5 0

2 years ago

What are the common denominator for 4/5and 1/3

Maru [420]

Answer:

15 is the answer hope this helps

7 0

1 year ago

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There are 1/6 gallons of water in a 2/3 gallon container. What fraction of the container is filled?

Ivenika [448]

Answer:

1/4

Step-by-step explanation:

2/3 multiply top and bottom of fraction by 2

4/6 is the capacity of the container

1/6 is filled

so 1/4 of the container is filled

6 0

2 years ago

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Distribute and simplify the radicals below (√12+6)(-√8-√2)

Hatshy [7]

For this case we have the following expression:

$(\sqrt {12} +6) (- \sqrt {8} - \sqrt {2})$

We apply distributive property:

$(\sqrt {12} * - \sqrt {8}) + (\sqrt {12} * - \sqrt {2}) + (6 * - \sqrt {8}) + (6 * - \sqrt {2} ) =\\- \sqrt {96} - \sqrt {24} -6 \sqrt {8} -6 \sqrt {2} =$

We rewrite in equivalent form:

$- \sqrt {4 ^ 2 * 6} - \sqrt {2 ^ 2 * 6} -6 \sqrt {2 ^ 2 * 2} -6 \sqrt {2} =\\-4 \sqrt {6} -2 \sqrt {6} -6 * 2 \sqrt {2} -6 \sqrt {2} =$

$-4 \sqrt {6} -2 \sqrt {6} -12 \sqrt {2} -6 \sqrt {2} =\\-6 \sqrt {6} -18 \sqrt {2}$

Answer:

$-6 \sqrt {6} -18 \sqrt {2}$

8 0

2 years ago

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