That is when h=0
so assuming yo meant
h(t)=-16t²+24t+16
solve for t such that h(t)=0
because when height=0, the gymnast hits the ground
so
0=-16t²+24t+16
using math (imma complete the square
0=-16(t²-3/2t)+16
0=-16(t²-3/2t+9/16-9/16)+16
0=-16((t-3/4)²-9/16)+16
0=-16(t-3/4)²+9+16
0=-16(t-3/4)²+25
-25=-16(t-3/4)²
25/16=(t-3/4)²
sqrt both sides
+/-5/4=t-3/4
3/4+/-5/4=t
if we do plus (because minus would give us negative height)
8/4=t
2=t
it takes 2 seconds
50 inches 4/5*x=40
x=40/(4/5)
x=40*5/4=200/4=50 x=50 inches
X=-4-y there you go enjoy
Answer:
D
Step-by-step explanation:
But basically, one by one you try moving the terms out of the radical.
75 is also 25 * 3 and since 25 has a perfect square root of 5 that goes out and 3 stays inside the radical.
x^3 is also x^2 * x and since x^2 has a perfect square root which is just x that goes outside while the remaining x stays inside.
y^9 is also y^8 * y and since we move variables out the radical in twos y^ goes outside the radical and y stays inside alone.
Finally, z is just z it can't be taken out so it stays inside the radical.
Hope that helps!
Answer:
c
Step-by-step explanation:
i made a 90 on edge
