I am a 2-digit number. The sum of my digits is 16. My ten’s digit is greater than my one’s digit. What number am I?
1 answer:
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Let z = 3x+2. Then, by substitution, your equation is
.. z^2 +7z -8 = 0
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This equation can be factored as
.. (z +8)(z -1) = 0
.. x = -8 or +1
Then
.. 3x +2 = -8 or +1
.. 3x = -10 or -1
.. x = -10/3 or -1/3
.. z^2 +7z -8 = 0
_____
This equation can be factored as
.. (z +8)(z -1) = 0
.. x = -8 or +1
Then
.. 3x +2 = -8 or +1
.. 3x = -10 or -1
.. x = -10/3 or -1/3