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2 years ago

13

What is the math word that we use if a thinki graph "flips"? (hint: it starts with an "r")

1 answer:

adelina 88 [10]2 years ago

7 0

Answer:

reflection

Step-by-step explanation:

mirror= reflection

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How to evaluate the expression

jasenka [17]

Answer:

1

Step-by-step explanation:

$4^{5}$ can be expressed as $2^{(2)(5)}$ = $2^{10}$

Similarly $4^{8}$ can be expressed as $2^{(2)(8)}$ = $2^{16}$

Numerator becomes:

$2^{10}$ · $-2^{9}$ = $-2^{19}$

Denominator becomes:

$2^{16}$ · $-2^{3}$ = $-2^{19}$

Since numerator = Denominator,

Answer = 1

Edit reason: typo

4 0

2 years ago

Point Q' is the image of Q (4,-6) is under a translation by 1 unit to the right.

alexandr1967 [171]

Answer:

The coordinates of point Q' would be (5, -6) after being translated 1 unit to the right.

Step-by-step explanation:

4 0

2 years ago

It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

2 years ago

1<br> Find the slope of the following graph and write your result in the empty box.<br> Answer:

Viktor [21]

Answer:

y = 2x

Step-by-step explanation:

Slope = $\frac{y}{x} =\frac{2}{1}$

4 0

2 years ago

Which function has the same y-intercept as the one below

Over [174]

Check the picture below, so let's check the equations below hmmm

$\boxed{A}\\\\ y=\cfrac{16-3x}{4}\implies y=\cfrac{-3x+16}{4}\implies y = \cfrac{-3x}{4}+\cfrac{16}{4}\implies y=-\cfrac{3}{4}x\stackrel{\stackrel{b}{\downarrow }}{+4}~\hfill \bigotimes \\\\[-0.35em] ~\dotfill$

$\boxed{D}\\\\ y+4=2x\implies y=2x\underset{\stackrel{\uparrow }{b}}{-4}\qquad \textit{\Large \checkmark}\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

5 0

1 year ago